Optimal. Leaf size=118 \[ \frac{\left (a^2 B-2 a b C-b^2 B\right ) \cot (c+d x)}{d}+x \left (a^2 B-2 a b C-b^2 B\right )-\frac{a^2 B \cot ^3(c+d x)}{3 d}+\frac{\left (b^2 C-a (a C+2 b B)\right ) \log (\sin (c+d x))}{d}-\frac{a (a C+2 b B) \cot ^2(c+d x)}{2 d} \]
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Rubi [A] time = 0.31102, antiderivative size = 118, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.15, Rules used = {3632, 3604, 3628, 3529, 3531, 3475} \[ \frac{\left (a^2 B-2 a b C-b^2 B\right ) \cot (c+d x)}{d}+x \left (a^2 B-2 a b C-b^2 B\right )-\frac{a^2 B \cot ^3(c+d x)}{3 d}+\frac{\left (b^2 C-a (a C+2 b B)\right ) \log (\sin (c+d x))}{d}-\frac{a (a C+2 b B) \cot ^2(c+d x)}{2 d} \]
Antiderivative was successfully verified.
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Rule 3632
Rule 3604
Rule 3628
Rule 3529
Rule 3531
Rule 3475
Rubi steps
\begin{align*} \int \cot ^5(c+d x) (a+b \tan (c+d x))^2 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx &=\int \cot ^4(c+d x) (a+b \tan (c+d x))^2 (B+C \tan (c+d x)) \, dx\\ &=-\frac{a^2 B \cot ^3(c+d x)}{3 d}+\int \cot ^3(c+d x) \left (a (2 b B+a C)-\left (a^2 B-b^2 B-2 a b C\right ) \tan (c+d x)+b^2 C \tan ^2(c+d x)\right ) \, dx\\ &=-\frac{a (2 b B+a C) \cot ^2(c+d x)}{2 d}-\frac{a^2 B \cot ^3(c+d x)}{3 d}+\int \cot ^2(c+d x) \left (-a^2 B+b^2 B+2 a b C+\left (b^2 C-a (2 b B+a C)\right ) \tan (c+d x)\right ) \, dx\\ &=\frac{\left (a^2 B-b^2 B-2 a b C\right ) \cot (c+d x)}{d}-\frac{a (2 b B+a C) \cot ^2(c+d x)}{2 d}-\frac{a^2 B \cot ^3(c+d x)}{3 d}+\int \cot (c+d x) \left (b^2 C-a (2 b B+a C)+\left (a^2 B-b^2 B-2 a b C\right ) \tan (c+d x)\right ) \, dx\\ &=\left (a^2 B-b^2 B-2 a b C\right ) x+\frac{\left (a^2 B-b^2 B-2 a b C\right ) \cot (c+d x)}{d}-\frac{a (2 b B+a C) \cot ^2(c+d x)}{2 d}-\frac{a^2 B \cot ^3(c+d x)}{3 d}+\left (b^2 C-a (2 b B+a C)\right ) \int \cot (c+d x) \, dx\\ &=\left (a^2 B-b^2 B-2 a b C\right ) x+\frac{\left (a^2 B-b^2 B-2 a b C\right ) \cot (c+d x)}{d}-\frac{a (2 b B+a C) \cot ^2(c+d x)}{2 d}-\frac{a^2 B \cot ^3(c+d x)}{3 d}+\frac{\left (b^2 C-a (2 b B+a C)\right ) \log (\sin (c+d x))}{d}\\ \end{align*}
Mathematica [C] time = 1.1463, size = 152, normalized size = 1.29 \[ \frac{6 \left (a^2 B-2 a b C-b^2 B\right ) \cot (c+d x)-6 \left (a^2 C+2 a b B-b^2 C\right ) \log (\tan (c+d x))-2 a^2 B \cot ^3(c+d x)-3 a (a C+2 b B) \cot ^2(c+d x)+3 (a+i b)^2 (C-i B) \log (-\tan (c+d x)+i)+3 (a-i b)^2 (C+i B) \log (\tan (c+d x)+i)}{6 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.093, size = 188, normalized size = 1.6 \begin{align*} -{b}^{2}Bx-{\frac{B\cot \left ( dx+c \right ){b}^{2}}{d}}-{\frac{B{b}^{2}c}{d}}+{\frac{{b}^{2}C\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}-{\frac{Bab \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{d}}-2\,{\frac{Bab\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}-2\,Cabx-2\,{\frac{C\cot \left ( dx+c \right ) ab}{d}}-2\,{\frac{Cabc}{d}}-{\frac{{a}^{2}B \left ( \cot \left ( dx+c \right ) \right ) ^{3}}{3\,d}}+{\frac{B\cot \left ( dx+c \right ){a}^{2}}{d}}+{a}^{2}Bx+{\frac{{a}^{2}Bc}{d}}-{\frac{C{a}^{2} \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{2\,d}}-{\frac{C{a}^{2}\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.68782, size = 201, normalized size = 1.7 \begin{align*} \frac{6 \,{\left (B a^{2} - 2 \, C a b - B b^{2}\right )}{\left (d x + c\right )} + 3 \,{\left (C a^{2} + 2 \, B a b - C b^{2}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) - 6 \,{\left (C a^{2} + 2 \, B a b - C b^{2}\right )} \log \left (\tan \left (d x + c\right )\right ) - \frac{2 \, B a^{2} - 6 \,{\left (B a^{2} - 2 \, C a b - B b^{2}\right )} \tan \left (d x + c\right )^{2} + 3 \,{\left (C a^{2} + 2 \, B a b\right )} \tan \left (d x + c\right )}{\tan \left (d x + c\right )^{3}}}{6 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.50593, size = 367, normalized size = 3.11 \begin{align*} -\frac{3 \,{\left (C a^{2} + 2 \, B a b - C b^{2}\right )} \log \left (\frac{\tan \left (d x + c\right )^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) \tan \left (d x + c\right )^{3} + 3 \,{\left (C a^{2} + 2 \, B a b - 2 \,{\left (B a^{2} - 2 \, C a b - B b^{2}\right )} d x\right )} \tan \left (d x + c\right )^{3} + 2 \, B a^{2} - 6 \,{\left (B a^{2} - 2 \, C a b - B b^{2}\right )} \tan \left (d x + c\right )^{2} + 3 \,{\left (C a^{2} + 2 \, B a b\right )} \tan \left (d x + c\right )}{6 \, d \tan \left (d x + c\right )^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 47.6416, size = 258, normalized size = 2.19 \begin{align*} \begin{cases} \text{NaN} & \text{for}\: \left (c = 0 \vee c = - d x\right ) \wedge \left (c = - d x \vee d = 0\right ) \\x \left (a + b \tan{\left (c \right )}\right )^{2} \left (B \tan{\left (c \right )} + C \tan ^{2}{\left (c \right )}\right ) \cot ^{5}{\left (c \right )} & \text{for}\: d = 0 \\B a^{2} x + \frac{B a^{2}}{d \tan{\left (c + d x \right )}} - \frac{B a^{2}}{3 d \tan ^{3}{\left (c + d x \right )}} + \frac{B a b \log{\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{d} - \frac{2 B a b \log{\left (\tan{\left (c + d x \right )} \right )}}{d} - \frac{B a b}{d \tan ^{2}{\left (c + d x \right )}} - B b^{2} x - \frac{B b^{2}}{d \tan{\left (c + d x \right )}} + \frac{C a^{2} \log{\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} - \frac{C a^{2} \log{\left (\tan{\left (c + d x \right )} \right )}}{d} - \frac{C a^{2}}{2 d \tan ^{2}{\left (c + d x \right )}} - 2 C a b x - \frac{2 C a b}{d \tan{\left (c + d x \right )}} - \frac{C b^{2} \log{\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} + \frac{C b^{2} \log{\left (\tan{\left (c + d x \right )} \right )}}{d} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.0847, size = 451, normalized size = 3.82 \begin{align*} \frac{B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 3 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 6 \, B a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 15 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 24 \, C a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 12 \, B b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 24 \,{\left (B a^{2} - 2 \, C a b - B b^{2}\right )}{\left (d x + c\right )} + 24 \,{\left (C a^{2} + 2 \, B a b - C b^{2}\right )} \log \left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right ) - 24 \,{\left (C a^{2} + 2 \, B a b - C b^{2}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) + \frac{44 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 88 \, B a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 44 \, C b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 15 \, B a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 24 \, C a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 12 \, B b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 3 \, C a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 6 \, B a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - B a^{2}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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